Edunes Online EducationConsider the set:
A = {x : x is a student of Class XI presently studying in a school}The number of students in Class XI can be counted. Hence, set A contains a finite number of elements.
Now consider another set:
B = {x : x is a student presently studying in both Classes X and XI}A student cannot study in two different classes at the same time. Hence, set B contains no element.
Set A has 5 elements, set B has 6 elements, and set C has a large but definite number of elements.
The number of elements of a set \(S\) is denoted by:
\[ n(S) \] \[ n(A) = 5 \] \[ n(B) = 6 \]Days of the week:
\[ W = \{Monday,\;Tuesday,\;\ldots\} \]W is a finite set.
Solutions of:
\[ x^2 - 16 = 0 \] \[ x^2 = 16 \] \[ x = \pm 4 \]Finite set.
These sets never end, hence they are infinite.
Finite set
Finite set
Not a natural number β Empty β Finite
Set of all prime numbers β Infinite
Set of all odd natural numbers β Infinite
Given two sets A and B,
if every element of A is also an element of B and
if every element of B is also an element of A,
then the sets A and B are said to be equal.
A = B
Clearly, the two sets have exactly the same elements.
We consider the following examples :
(i) Let A = {1, 2, 3, 4} and B = {3, 1, 4, 2}. Then A = B.
(ii) Let A be the set of prime numbers less than 6 and P the set of prime factors
of 30. Then A and P are equal, since 2, 3 and 5 are the only prime factors of
30 and also these are less than 6.
A set does not change if one or more elements of the set are repeated. For example, the sets A = {1, 2, 3} and B = {2, 2, 1, 3, 3} are equal, since each element of A is in B and vice-versa. That is why we generally do not repeat any element in describing a set.
Solutions: (i) We have, X = {A, L, L, O, Y}, B = {L, O, Y, A, L}. Then X and B are
equal sets as repetition of elements in a set do not change a set. Thus,
X = {A, L, O, Y} = B
(ii) A = {β2, β1, 0, 1, 2}, B = {1, 2}. Since 0 β A and 0 β B, A and B are not equal sets.